What is (\partial)/(\partial y)(x^2y^2) ?

The answer to (\partial)/(\partial y)(x^2y^2) is 2x^2y

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(\partial)/(\partial y)(x^2y^2)

\frac{\partial}{\partial y} (x^{2} y^{2})

2 x^{2} y

Solution steps

\frac{\partial}{\partial y} (x^{2} y^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= x^{2} \cdot 2 y^{2 - 1}

Simplify

= 2 x^{2} y

w \to 0 lim (\frac{1 - cos ( 5 w )}{w})

\int_{1}^{2} (4 x^{3} - 6 x) d x

\int_{0}^{x} (2 x - y) d y

\int (1 + 3 x)^{2} d x

n = 1 \sum \infty arctan (15 n)

What is (\partial)/(\partial y)(x^2y^2) ?
The answer to (\partial)/(\partial y)(x^2y^2) is 2x^2y