What is the derivative of-(x-1^2+3) ?

The derivative of-(x-1^2+3) is -2x+2

What is the first derivative of-(x-1^2+3) ?

The first derivative of-(x-1^2+3) is -2x+2

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\frac{d}{d x} (- (x - 1)^{2} + 3)

- 2 x + 2

Solution steps

\frac{d}{d x} (- (x - 1)^{2} + 3)

Simplify

- (x - 1)^{2} + 3 : - x^{2} + 2 x + 2

= \frac{d}{d x} (- x^{2} + 2 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (2) = 0

= - 2 x + 2 + 0

Simplify

= - 2 x + 2

\frac{d}{d x} (\frac{12 x ^{6} - 3 x ^{2} + x ^{2}}{3 x ^{4}})

\int cos (x) \cdot sin^{2} (x) d x

\int x^{\frac{5}{3}} d x

\int sec^{2} (8 x) d x

(y \cdot e^{- x}) \frac{d y}{d x} = x

What is the derivative of-(x-1^2+3) ?
The derivative of-(x-1^2+3) is -2x+2
What is the first derivative of-(x-1^2+3) ?
The first derivative of-(x-1^2+3) is -2x+2