What is the sum from n=0 to infinity of n/(3^n) ?

The sum from n=0 to infinity of n/(3^n) is converges

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sum from n=0 to infinity of n/(3^n)

n = 0 \sum \infty \frac{n}{3 ^{n}}

converges

Solution steps

n = 0 \sum \infty \frac{n}{3 ^{n}}

Apply Series Ratio Test:

converges

= converges

f (x) = arccos (2 x)

x \to 0 + lim (\frac{e ^{\frac{1}{x}}}{x})

(3 x + 4)^{2}

\frac{d}{d t} (2 t - 1)

\frac{\partial}{\partial x} (- x e^{\frac{y}{x}})

What is the sum from n=0 to infinity of n/(3^n) ?
The sum from n=0 to infinity of n/(3^n) is converges