What is (\partial)/(\partial x)(y-yx^2) ?

The answer to (\partial)/(\partial x)(y-yx^2) is -2yx

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(\partial)/(\partial x)(y-yx^2)

\frac{\partial}{\partial x} (y - y x^{2})

- 2 y x

Solution steps

\frac{\partial}{\partial x} (y - y x^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (y x^{2})

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (y x^{2}) = 2 y x

= 0 - 2 y x

Simplify

= - 2 y x

f (x) = \frac{14 x + 4 x ^{2}}{( 7 + 4 x ) ^{2}}

\frac{\partial}{\partial x} (- 2 k l (ln (\frac{y}{- x - y})))

\int \frac{1}{6 - x} d x

g (x) = 2 x - 3

\int 14 θ sec^{2} (θ) d θ

What is (\partial)/(\partial x)(y-yx^2) ?
The answer to (\partial)/(\partial x)(y-yx^2) is -2yx