What is the derivative of g(x)=sqrt(2x-3) ?

The derivative of g(x)=sqrt(2x-3) is 1/(sqrt(2x-3))

What is the first derivative of g(x)=sqrt(2x-3) ?

The first derivative of g(x)=sqrt(2x-3) is 1/(sqrt(2x-3))

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derivative of

g (x) = 2 x - 3

\frac{1}{2 x - 3}

Solution steps

\frac{d}{d x} (2 x - 3)

Apply the chain rule:

\frac{1}{2 2 x - 3} \frac{d}{d x} (2 x - 3)

= \frac{1}{2 2 x - 3} \frac{d}{d x} (2 x - 3)

\frac{d}{d x} (2 x - 3) = 2

= \frac{1}{2 2 x - 3} \cdot 2

Simplify

\frac{1}{2 2 x - 3} \cdot 2 : \frac{1}{2 x - 3}

= \frac{1}{2 x - 3}

\int 14 θ sec^{2} (θ) d θ

\frac{d}{d x} (9 - x^{2} - y^{2})

3 (x^{3} - x^{2})

\int \frac{3 e ^{x}}{e ^{2 x} + 6 e ^{x} + 9} d x

y^{^{'}} + 2 y = 16

What is the derivative of g(x)=sqrt(2x-3) ?
The derivative of g(x)=sqrt(2x-3) is 1/(sqrt(2x-3))
What is the first derivative of g(x)=sqrt(2x-3) ?
The first derivative of g(x)=sqrt(2x-3) is 1/(sqrt(2x-3))