What is the derivative of 9-x^2-y^2 ?

The derivative of 9-x^2-y^2 is -2x-2y(dy)/(dx)

What is the first derivative of 9-x^2-y^2 ?

The first derivative of 9-x^2-y^2 is -2x-2y(dy)/(dx)

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\frac{d}{d x} (9 - x^{2} - y^{2})

- 2 x - 2 y \frac{d y}{d x}

Solution steps

\frac{d}{d x} (9 - x^{2} - y^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9) - \frac{d}{d x} (x^{2}) - \frac{d}{d x} (y^{2})

\frac{d}{d x} (9) = 0

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (y^{2}) = 2 y \frac{d y}{d x}

= 0 - 2 x - 2 y \frac{d y}{d x}

Simplify

= - 2 x - 2 y \frac{d y}{d x}

3 (x^{3} - x^{2})

\int \frac{3 e ^{x}}{e ^{2 x} + 6 e ^{x} + 9} d x

y^{^{'}} + 2 y = 16

\int x (x^{2} - 1)^{5} d x

\frac{d ^{2}}{d x ^{2}} (e^{x} - x^{5})

What is the derivative of 9-x^2-y^2 ?
The derivative of 9-x^2-y^2 is -2x-2y(dy)/(dx)
What is the first derivative of 9-x^2-y^2 ?
The first derivative of 9-x^2-y^2 is -2x-2y(dy)/(dx)