What is the first (x+1/x)^' ?

The first (x+1/x)^' is 1-1/(x^2)

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(x+1/x)^'

(x + \frac{1}{x})^{^{'}}

1 - \frac{1}{x ^{2}}

Solution steps

(x + \frac{1}{x})^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x^{^{'}} + (\frac{1}{x})^{^{'}}

x^{'} = 1

(\frac{1}{x})^{'} = - \frac{1}{x ^{2}}

= 1 - \frac{1}{x ^{2}}

[x + (x + sin^{2} (x))^{3}]^{5}

\frac{d}{d x} (\frac{ln ( x + 1 )}{4 x + 2})

\int sec^{3} (4 x) d x

\frac{d}{d x} (1 \frac{1}{x})

\frac{d}{d x} ((3 x + 1)^{6} 2 x - 5)