What is the derivative of [x+(x+sin^2(x))^3]^5 ?

The derivative of [x+(x+sin^2(x))^3]^5 is 5(x+(x+sin^2(x))^3)^4(1+3(x+sin^2(x))^2(1+sin(2x)))

What is the first derivative of [x+(x+sin^2(x))^3]^5 ?

The first derivative of [x+(x+sin^2(x))^3]^5 is 5(x+(x+sin^2(x))^3)^4(1+3(x+sin^2(x))^2(1+sin(2x)))

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derivative of

[x + (x + sin^{2} (x))^{3}]^{5}

5 (x + (x + sin^{2} (x))^{3})^{4} (1 + 3 (x + sin^{2} (x))^{2} (1 + sin (2 x)))

Solution steps

\frac{d}{d x} ((x + (x + sin^{2} (x))^{3})^{5})

Apply the chain rule:

5 (x + (x + sin^{2} (x))^{3})^{4} \frac{d}{d x} (x + (x + sin^{2} (x))^{3})

= 5 (x + (x + sin^{2} (x))^{3})^{4} \frac{d}{d x} (x + (x + sin^{2} (x))^{3})

\frac{d}{d x} (x + (x + sin^{2} (x))^{3}) = 1 + 3 (x + sin^{2} (x))^{2} (1 + sin (2 x))

= 5 (x + (x + sin^{2} (x))^{3})^{4} (1 + 3 (x + sin^{2} (x))^{2} (1 + sin (2 x)))

\frac{d}{d x} (\frac{ln ( x + 1 )}{4 x + 2})

\int sec^{3} (4 x) d x

\frac{d}{d x} (1 \frac{1}{x})

\frac{d}{d x} ((3 x + 1)^{6} 2 x - 5)

\int 2 x d x

What is the derivative of [x+(x+sin^2(x))^3]^5 ?
The derivative of [x+(x+sin^2(x))^3]^5 is 5(x+(x+sin^2(x))^3)^4(1+3(x+sin^2(x))^2(1+sin(2x)))
What is the first derivative of [x+(x+sin^2(x))^3]^5 ?
The first derivative of [x+(x+sin^2(x))^3]^5 is 5(x+(x+sin^2(x))^3)^4(1+3(x+sin^2(x))^2(1+sin(2x)))