What is the integral of 2sqrt(x) ?

The integral of 2sqrt(x) is 4/3 x^{3/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2sqrt(x)

\int 2 x d x

\frac{4}{3} x^{\frac{3}{2}} + C

Solution steps

\int 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x d x

Apply the Power Rule

: \frac{2}{3} x^{\frac{3}{2}}

= 2 \cdot \frac{2}{3} x^{\frac{3}{2}}

Simplify

2 \cdot \frac{2}{3} x^{\frac{3}{2}} : \frac{4}{3} x^{\frac{3}{2}}

= \frac{4}{3} x^{\frac{3}{2}}

Add a constant to the solution

= \frac{4}{3} x^{\frac{3}{2}} + C

\frac{d}{d r} (r^{3})

f (x) = arctan (4 x)

\int (5 x^{3} - 2 x^{2} + 3) d x

x \to 0 lim (\frac{e ^{x} - 1}{6 x})

\int x^{4} - 4 x^{2} + 4 d x