What is the derivative of 8/(2x+3) ?

The derivative of 8/(2x+3) is -(16)/((2x+3)^2)

What is the first derivative of 8/(2x+3) ?

The first derivative of 8/(2x+3) is -(16)/((2x+3)^2)

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\frac{d}{d x} (\frac{8}{2 x + 3})

- \frac{16}{( 2 x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{8}{2 x + 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (\frac{1}{2 x + 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 8 \frac{d}{d x} ((2 x + 3)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x + 3 ) ^{2}} \frac{d}{d x} (2 x + 3)

= - \frac{1}{( 2 x + 3 ) ^{2}} \frac{d}{d x} (2 x + 3)

\frac{d}{d x} (2 x + 3) = 2

= 8 (- \frac{1}{( 2 x + 3 ) ^{2}} \cdot 2)

Simplify

8 (- \frac{1}{( 2 x + 3 ) ^{2}} \cdot 2) : - \frac{16}{( 2 x + 3 ) ^{2}}

= - \frac{16}{( 2 x + 3 ) ^{2}}

\int (x^{\frac{1}{3}} - 3^{\frac{1}{3}}) d x

\frac{d}{d x} (x^{9} ln (7 x))

n = 1 \sum \infty \frac{1}{4 n ^{2} + 5}

\frac{d}{d x} (\frac{5 - sec ( x )}{tan ( x )})

y = 9

What is the derivative of 8/(2x+3) ?
The derivative of 8/(2x+3) is -(16)/((2x+3)^2)
What is the first derivative of 8/(2x+3) ?
The first derivative of 8/(2x+3) is -(16)/((2x+3)^2)