What is the derivative of 569+t(37t^{0.6}-108) ?

The derivative of 569+t(37t^{0.6}-108) is 59.2t^{0.6}-108

What is the first derivative of 569+t(37t^{0.6}-108) ?

The first derivative of 569+t(37t^{0.6}-108) is 59.2t^{0.6}-108

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derivative of

569 + t (37 t^{0.6} - 108)

59.2 t^{0.6} - 108

Solution steps

\frac{d}{d t} (569 + t (37 t^{0.6} - 108))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (569) + \frac{d}{d t} (t (37 t^{0.6} - 108))

\frac{d}{d t} (569) = 0

\frac{d}{d t} (t (37 t^{0.6} - 108)) = 59.2 t^{0.6} - 108

= 0 + 59.2 t^{0.6} - 108

Simplify

= 59.2 t^{0.6} - 108

\frac{d r}{d θ} = \frac{r ^{2} + 10 r θ}{5 θ ^{2}}

\int 5 e^{2 x - 1} d x

y^{^{''}} - 18 y^{^{'}} + 77 y = 0

\int x^{- 2} ln (x) d x

\int x^{5} sin (x^{2}) d x

What is the derivative of 569+t(37t^{0.6}-108) ?
The derivative of 569+t(37t^{0.6}-108) is 59.2t^{0.6}-108
What is the first derivative of 569+t(37t^{0.6}-108) ?
The first derivative of 569+t(37t^{0.6}-108) is 59.2t^{0.6}-108