What is the solution for (dr)/(dθ)=(r^2+10rθ)/(5θ^2) ?

The solution for (dr)/(dθ)=(r^2+10rθ)/(5θ^2) is r(θ)=(5θ^2)/(-θ+c_{1)}

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(dr)/(dθ)=(r^2+10rθ)/(5θ^2)

\frac{d r}{d θ} = \frac{r ^{2} + 10 r θ}{5 θ ^{2}}

r (θ) = \frac{5 θ ^{2}}{- θ + c _{1}}

Solution steps

\frac{d r}{d θ} = \frac{r ^{2} + 10 r θ}{5 θ ^{2}}

Solve Bernoulli ODE:

r (θ) = \frac{5 θ ^{2}}{- θ + c _{1}}

r (θ) = \frac{5 θ ^{2}}{- θ + c _{1}}

\int 5 e^{2 x - 1} d x

y^{^{''}} - 18 y^{^{'}} + 77 y = 0

\int x^{- 2} ln (x) d x

\int x^{5} sin (x^{2}) d x

y = \frac{x + 1}{5 - x}, (7, - 4)

What is the solution for (dr)/(dθ)=(r^2+10rθ)/(5θ^2) ?
The solution for (dr)/(dθ)=(r^2+10rθ)/(5θ^2) is r(θ)=(5θ^2)/(-θ+c_{1)}