What is the derivative of (x^2-2^2) ?

The derivative of (x^2-2^2) is 4x(x^2-2)

What is the first derivative of (x^2-2^2) ?

The first derivative of (x^2-2^2) is 4x(x^2-2)

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\frac{d}{d x} ((x^{2} - 2)^{2})

4 x (x^{2} - 2)

Solution steps

\frac{d}{d x} ((x^{2} - 2)^{2})

Apply the chain rule:

2 (x^{2} - 2) \frac{d}{d x} (x^{2} - 2)

= 2 (x^{2} - 2) \frac{d}{d x} (x^{2} - 2)

\frac{d}{d x} (x^{2} - 2) = 2 x

= 2 (x^{2} - 2) \cdot 2 x

Simplify

= 4 x (x^{2} - 2)

\frac{11 - x}{7} + \frac{36 + x ^{2}}{3}

\int_{0}^{9} ∣ 2 x - 9 ∣ d x

x \to 3 - lim (\frac{e ^{2}}{x - 3})

\int \frac{x ^{2}}{( 1 - x ^{3} ) ^{5}} d x

\frac{d}{d x} (\frac{1}{x ^{2} + 3})

What is the derivative of (x^2-2^2) ?
The derivative of (x^2-2^2) is 4x(x^2-2)
What is the first derivative of (x^2-2^2) ?
The first derivative of (x^2-2^2) is 4x(x^2-2)