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Popular >

3y^{''}+4y^'=0

Solution

3 y^{^{''}} + 4 y^{^{'}} = 0

Solution

y = c_{1} + c_{2} e^{- \frac{4 t}{3}}

Solution steps

3 y^{''} (t) + 4 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{4 t}{3}}

y = c_{1} + c_{2} e^{- \frac{4 t}{3}}

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Frequently Asked Questions (FAQ)

What is the solution for 3y^{''}+4y^'=0 ?
The solution for 3y^{''}+4y^'=0 is y=c_{1}+c_{2}e^{-(4t)/3}