What is the integral of (-1)/(y^2) ?

The integral of (-1)/(y^2) is 1/y+C

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integral of (-1)/(y^2)

\int \frac{- 1}{y ^{2}} d y

\frac{1}{y} + C

Solution steps

\int \frac{- 1}{y ^{2}} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{y ^{2}} d y

Apply the Power Rule

: - \frac{1}{y}

= - (- \frac{1}{y})

Simplify

= \frac{1}{y}

Add a constant to the solution

= \frac{1}{y} + C

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