What is (\partial}{\partial x}(\frac{y-z)/x) ?

The answer to (\partial}{\partial x}(\frac{y-z)/x) is -(y-z)/(x^2)

Popular >

(\partial}{\partial x}(\frac{y-z)/x)

\frac{\partial}{\partial x} (\frac{y - z}{x})

- \frac{y - z}{x ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{y - z}{x})

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (y - z) \frac{\partial}{\partial x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= (y - z) \frac{\partial}{\partial x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= (y - z) (- 1 \cdot x^{- 1 - 1})

Simplify

(y - z) (- 1 \cdot x^{- 1 - 1}) : - \frac{y - z}{x ^{2}}

= - \frac{y - z}{x ^{2}}

\int_{0}^{1} (x - x)^{2} d x

\frac{s - 4}{s ^{2} - 8 s + 10}

t^{\frac{4}{3}}

f (x) = x^{3} - 9 x + 4, (3, 4)

\frac{d y}{d x} = \frac{( x - y )}{( x + y )}

What is (\partial}{\partial x}(\frac{y-z)/x) ?
The answer to (\partial}{\partial x}(\frac{y-z)/x) is -(y-z)/(x^2)