What is the slope ofintercept (-1,1),(1,0) ?

The slope ofintercept (-1,1),(1,0) is y=-1/2 x+1/2

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slope ofintercept (-1,1),(1,0)

slope intercept

(- 1, 1), (1, 0)

y = - \frac{1}{2} x + \frac{1}{2}

Solution steps

Compute the slope

(- 1, 1), (1, 0) : m = - \frac{1}{2}

Compute the

y

intercept:

b = \frac{1}{2}

Construct the line equation

y = mx + b

where

m = - \frac{1}{2}

and

b = \frac{1}{2}

y = - \frac{1}{2} x + \frac{1}{2}

\frac{d}{d x} (\frac{2}{cos ( 7 x )})

f (x) = x^{4}

\frac{d}{d t} (- 5 sin (t))

y = x + \frac{2}{x}, (2, 3)

\int t^{4} e^{- t^{5}} d t

What is the slope ofintercept (-1,1),(1,0) ?
The slope ofintercept (-1,1),(1,0) is y=-1/2 x+1/2