What is (\partial)/(\partial x)(-5y^4sin(5x)) ?

The answer to (\partial)/(\partial x)(-5y^4sin(5x)) is -25y^4cos(5x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(-5y^4sin(5x))

\frac{\partial}{\partial x} (- 5 y^{4} sin (5 x))

- 25 y^{4} cos (5 x)

Solution steps

\frac{\partial}{\partial x} (- 5 y^{4} sin (5 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 5 y^{4} \frac{\partial}{\partial x} (sin (5 x))

Apply the chain rule:

cos (5 x) \frac{\partial}{\partial x} (5 x)

= cos (5 x) \frac{\partial}{\partial x} (5 x)

\frac{\partial}{\partial x} (5 x) = 5

= - 5 y^{4} cos (5 x) \cdot 5

Simplify

= - 25 y^{4} cos (5 x)

\frac{d y}{d x} = \frac{3 x - 9}{2 x + 8}

x \to 0 lim (\frac{1 - e ^{- 2 x}}{x})

\frac{d y}{d x} = 2 + e^{- 2 x + y + 1}

y = 2 x - 3 x^{2}

\frac{d}{d x} (cos^{3} (5 x))

What is (\partial)/(\partial x)(-5y^4sin(5x)) ?
The answer to (\partial)/(\partial x)(-5y^4sin(5x)) is -25y^4cos(5x)