What is the solution for (dy)/(dx)=2+e^{-2x+y+1} ?

The solution for (dy)/(dx)=2+e^{-2x+y+1} is y=-ln(-x-c_{1})+2x-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=2+e^{-2x+y+1}

\frac{d y}{d x} = 2 + e^{- 2 x + y + 1}

y = - ln (- x - c_{1}) + 2 x - 1

Solution steps

\frac{d y}{d x} = 2 + e^{- 2 x + y + 1}

Solve using substitution:

y = - ln (- x - c_{1}) + 2 x - 1

y = - ln (- x - c_{1}) + 2 x - 1

y = 2 x - 3 x^{2}

\frac{d}{d x} (cos^{3} (5 x))

\int_{0}^{1} \frac{2 t}{( 2 - t ) ^{2}} d t

\int \frac{x ^{3}}{x ^{2} - 9} d x

\frac{9}{( 1 - x ) ^{2}}

What is the solution for (dy)/(dx)=2+e^{-2x+y+1} ?
The solution for (dy)/(dx)=2+e^{-2x+y+1} is y=-ln(-x-c_{1})+2x-1