What is the derivative of 9/((1-x)^2) ?

The derivative of 9/((1-x)^2) is (18)/((1-x)^3)

What is the first derivative of 9/((1-x)^2) ?

The first derivative of 9/((1-x)^2) is (18)/((1-x)^3)

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derivative of

\frac{9}{( 1 - x ) ^{2}}

\frac{18}{( 1 - x ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{9}{( 1 - x ) ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{1}{( 1 - x ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 9 \frac{d}{d x} ((1 - x)^{- 2})

Apply the chain rule:

- \frac{2}{( 1 - x ) ^{3}} \frac{d}{d x} (1 - x)

= - \frac{2}{( 1 - x ) ^{3}} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= 9 (- \frac{2}{( 1 - x ) ^{3}} (- 1))

Simplify

9 (- \frac{2}{( 1 - x ) ^{3}} (- 1)) : \frac{18}{( 1 - x ) ^{3}}

= \frac{18}{( 1 - x ) ^{3}}

n = 1 \sum \infty \frac{1}{n ^{5}}

f (x) = (12 - x) 24 x - 144

y^{^{'''}} - y^{^{''}} + 6 y^{^{'}} - 6 y = 0

\frac{d y}{d x} = \frac{3 y}{x ^{2}}

(t + 2 y + 5) d t - d y = 0

What is the derivative of 9/((1-x)^2) ?
The derivative of 9/((1-x)^2) is (18)/((1-x)^3)
What is the first derivative of 9/((1-x)^2) ?
The first derivative of 9/((1-x)^2) is (18)/((1-x)^3)