What is the sum from n=1 to infinity of 1/(n^5) ?

The sum from n=1 to infinity of 1/(n^5) is converges

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sum from n=1 to infinity of 1/(n^5)

n = 1 \sum \infty \frac{1}{n ^{5}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{5}}

Apply p-Series Test:

converges

= converges

f (x) = (12 - x) 24 x - 144

y^{^{'''}} - y^{^{''}} + 6 y^{^{'}} - 6 y = 0

\frac{d y}{d x} = \frac{3 y}{x ^{2}}

(t + 2 y + 5) d t - d y = 0

\frac{d}{d x} ((\frac{3 x ^{2}}{2 x + 4})^{3})

What is the sum from n=1 to infinity of 1/(n^5) ?
The sum from n=1 to infinity of 1/(n^5) is converges