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Popular >

(t+2y+5)dt-dy=0

Solution

(t + 2 y + 5) d t - d y = 0

Solution

y = - \frac{t}{2} - \frac{11}{4} + c_{1} e^{2 t}

Solution steps

(t + 2 y + 5) d t - d y = 0

Solve linear ODE:

y = - \frac{t}{2} - \frac{11}{4} + c_{1} e^{2 t}

y = - \frac{t}{2} - \frac{11}{4} + c_{1} e^{2 t}

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\int cos (x) + sec^{2} (x) d x

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Frequently Asked Questions (FAQ)

What is the solution for (t+2y+5)dt-dy=0 ?
The solution for (t+2y+5)dt-dy=0 is y=-t/2-11/4+c_{1}e^{2t}