What is the integral of cos(x)+sec^2(x) ?

The integral of cos(x)+sec^2(x) is sin(x)+tan(x)+C

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integral of cos(x)+sec^2(x)

\int cos (x) + sec^{2} (x) d x

sin (x) + tan (x) + C

Solution steps

\int cos (x) + sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int cos (x) d x + \int sec^{2} (x) d x

\int cos (x) d x = sin (x)

\int sec^{2} (x) d x = tan (x)

= sin (x) + tan (x)

Add a constant to the solution

= sin (x) + tan (x) + C

\int 5 d x

x^{2} - 3 x + 2

\frac{\partial}{\partial x} (x + x y)

\int \frac{1}{sin ( x ) - cos ( x ) + 2} d x

\int 8 x sin (x) d x

What is the integral of cos(x)+sec^2(x) ?
The integral of cos(x)+sec^2(x) is sin(x)+tan(x)+C