What is (\partial)/(\partial x)(x+xy) ?

The answer to (\partial)/(\partial x)(x+xy) is 1+y

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(\partial)/(\partial x)(x+xy)

\frac{\partial}{\partial x} (x + x y)

1 + y

Solution steps

\frac{\partial}{\partial x} (x + x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (x y) = y

= 1 + y

\int \frac{1}{sin ( x ) - cos ( x ) + 2} d x

\int 8 x sin (x) d x

\frac{d}{d x} y = (x + y + 3)^{2}

\int 5 e^{6 - 3 x} d x

1 + 10 x - 1 - 3 x

What is (\partial)/(\partial x)(x+xy) ?
The answer to (\partial)/(\partial x)(x+xy) is 1+y