What is the sum from n=1 to infinity of 1/(n3^n) ?

The sum from n=1 to infinity of 1/(n3^n) is converges

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sum from n=1 to infinity of 1/(n3^n)

n = 1 \sum \infty \frac{1}{n 3 ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n \cdot 3 ^{n}}

Apply Series Ratio Test:

converges

= converges

{\frac{1}{s ^{3}}}

\int sin^{3} (15 x) d x

\frac{1}{( s ^{2} + 1 )}

f (x) = 4 ln (x)

f (x) = \frac{6}{4 x + 1}

What is the sum from n=1 to infinity of 1/(n3^n) ?
The sum from n=1 to infinity of 1/(n3^n) is converges