What is the integral from 1 to 2 of (1/8+3/8 x) ?

The integral from 1 to 2 of (1/8+3/8 x) is 11/16

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integral from 1 to 2 of (1/8+3/8 x)

\int_{1}^{2} (\frac{1}{8} + \frac{3}{8} x) d x

\frac{11}{16}

Decimal Notation

0.6875

Solution steps

\int_{1}^{2} \frac{1}{8} + \frac{3}{8} x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} \frac{1}{8} d x + \int_{1}^{2} \frac{3}{8} x d x

\int_{1}^{2} \frac{1}{8} d x = \frac{1}{8}

\int_{1}^{2} \frac{3}{8} x d x = \frac{9}{16}

= \frac{1}{8} + \frac{9}{16}

Simplify

\frac{1}{8} + \frac{9}{16} : \frac{11}{16}

= \frac{11}{16}

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What is the integral from 1 to 2 of (1/8+3/8 x) ?
The integral from 1 to 2 of (1/8+3/8 x) is 11/16