What is the integral from-infinity to 0 of 1/(5-2x) ?

The integral from-infinity to 0 of 1/(5-2x) is diverges

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integral from-infinity to 0 of 1/(5-2x)

\int_{- \infty}^{0} \frac{1}{5 - 2 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{5 - 2 x} d x

Compute the indefinite integral:

\int \frac{1}{5 - 2 x} d x = - \frac{1}{2} ln ∣ 5 - 2 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{5 - 2 x} d x =

diverges

= diverges

\frac{3 x}{7 x ^{2} + 1}

n = 1 \sum \infty \frac{5}{6 n + 4}

\frac{\partial}{\partial x} (16 - x^{2})

f (x) = \frac{cos ( x )}{2 + sin ( x )}

y^{^{''}} - 2 y^{^{'}} - 3 y = 10 e^{4 x}

What is the integral from-infinity to 0 of 1/(5-2x) ?
The integral from-infinity to 0 of 1/(5-2x) is diverges