What is the solution for -4t^2y^{''}+5ty^'-2y=0 ?

The solution for -4t^2y^{''}+5ty^'-2y=0 is y=c_{1}\sqrt[4]{t}+c_{2}t^2

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-4t^2y^{''}+5ty^'-2y=0

- 4 t^{2} y^{^{''}} + 5 t y^{^{'}} - 2 y = 0

Solution steps

- 4 t^{2} y^{''} (t) + 5 t y^{'} (t) - 2 y = 0

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What is the solution for -4t^2y^{''}+5ty^'-2y=0 ?
The solution for -4t^2y^{''}+5ty^'-2y=0 is y=c_{1}\sqrt[4]{t}+c_{2}t^2