What is the derivative of f(x)=sec^2(x)-1 ?

The derivative of f(x)=sec^2(x)-1 is 2tan(x)sec^2(x)

What is the first derivative of f(x)=sec^2(x)-1 ?

The first derivative of f(x)=sec^2(x)-1 is 2tan(x)sec^2(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = sec^{2} (x) - 1

2 tan (x) sec^{2} (x)

Solution steps

\frac{d}{d x} (sec^{2} (x) - 1)

Simplify

sec^{2} (x) - 1 : tan^{2} (x)

= \frac{d}{d x} (tan^{2} (x))

Apply the chain rule:

2 tan (x) \frac{d}{d x} (tan (x))

= 2 tan (x) \frac{d}{d x} (tan (x))

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= 2 tan (x) sec^{2} (x)

\int - 16 x^{2} d x

\int t^{2} sin (t^{3}) d t

\int (x - 1)^{10} (x + 3)^{2} d x

\int \frac{2 ^{x}}{5 ^{x}} d x

\frac{d}{d x} (\frac{3}{sin ( x ) + cos ( x )})

What is the derivative of f(x)=sec^2(x)-1 ?
The derivative of f(x)=sec^2(x)-1 is 2tan(x)sec^2(x)
What is the first derivative of f(x)=sec^2(x)-1 ?
The first derivative of f(x)=sec^2(x)-1 is 2tan(x)sec^2(x)