What is (\partial)/(\partial y)(x^4+x^2y) ?

The answer to (\partial)/(\partial y)(x^4+x^2y) is x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial y)(x^4+x^2y)

\frac{\partial}{\partial y} (x^{4} + x^{2} y)

x^{2}

Solution steps

\frac{\partial}{\partial y} (x^{4} + x^{2} y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{4}) + \frac{\partial}{\partial y} (x^{2} y)

\frac{\partial}{\partial y} (x^{4}) = 0

\frac{\partial}{\partial y} (x^{2} y) = x^{2}

= 0 + x^{2}

Simplify

= x^{2}

\frac{d}{d x} (\frac{x ^{2} + 3 x}{6})

\int_{0}^{16} x - 4 d x

y^{^{''}} + 2 y^{^{'}} + 10 y = 0, y (0) = 4, y^{^{'}} (0) = - 2

\frac{\partial}{\partial y} (x y)

x^{5} + y^{4} x^{6} + 5 y^{^{'}} = 0, y (0) = 0

What is (\partial)/(\partial y)(x^4+x^2y) ?
The answer to (\partial)/(\partial y)(x^4+x^2y) is x^2