What is the derivative of (x^2+3x/6) ?

The derivative of (x^2+3x/6) is 1/6 (2x+3)

What is the first derivative of (x^2+3x/6) ?

The first derivative of (x^2+3x/6) is 1/6 (2x+3)

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\frac{d}{d x} (\frac{x ^{2} + 3 x}{6})

\frac{1}{6} (2 x + 3)

Solution steps

\frac{d}{d x} (\frac{x ^{2} + 3 x}{6})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{6} \frac{d}{d x} (x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{6} (\frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

= \frac{1}{6} (2 x + 3)

\int_{0}^{16} x - 4 d x

y^{^{''}} + 2 y^{^{'}} + 10 y = 0, y (0) = 4, y^{^{'}} (0) = - 2

\frac{\partial}{\partial y} (x y)

x^{5} + y^{4} x^{6} + 5 y^{^{'}} = 0, y (0) = 0

\int sec (2 x) d x

What is the derivative of (x^2+3x/6) ?
The derivative of (x^2+3x/6) is 1/6 (2x+3)
What is the first derivative of (x^2+3x/6) ?
The first derivative of (x^2+3x/6) is 1/6 (2x+3)