What is the derivative of (8x)/(e^x) ?

The derivative of (8x)/(e^x) is (8(1-x))/(e^x)

What is the first derivative of (8x)/(e^x) ?

The first derivative of (8x)/(e^x) is (8(1-x))/(e^x)

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derivative of

\frac{8 x}{e ^{x}}

\frac{8 ( 1 - x )}{e ^{x}}

Solution steps

\frac{d}{d x} (\frac{8 x}{e ^{x}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (\frac{x}{e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 8 \cdot \frac{\frac{d x}{d x} e ^{x} - \frac{d}{d x} ( e ^{x} ) x}{( e ^{x} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 8 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}}

Simplify

8 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}} : \frac{8 ( 1 - x )}{e ^{x}}

= \frac{8 ( 1 - x )}{e ^{x}}

\int_{0}^{5} 5 x - 1 d x

\int_{0}^{1} (9 x^{e} + 2 e^{x}) d x

\frac{d y}{d x} = 2 x y^{2} + 3 x^{2} y^{2}

f (t) = \frac{cos ( t )}{t ^{7}}

x \to 2 lim (5 x - 2)

What is the derivative of (8x)/(e^x) ?
The derivative of (8x)/(e^x) is (8(1-x))/(e^x)
What is the first derivative of (8x)/(e^x) ?
The first derivative of (8x)/(e^x) is (8(1-x))/(e^x)