What is laplacetransform cos(2(t+1)) ?

The answer to laplacetransform cos(2(t+1)) is (cos(2)s-2sin(2))/(s^2+4)

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laplacetransform cos(2(t+1))

laplace transform

cos (2 (t + 1))

\frac{cos ( 2 ) s - 2 sin ( 2 )}{s ^{2} + 4}

Solution steps

L {cos (2 (t + 1))}

Use Laplace Transform table:

L {cos (a t + b)} = \frac{s \cdot cos ( b ) - a \cdot sin ( b )}{s ^{2} + a ^{2}}

L {cos (2 (t + 1))} = \frac{s cos ( 2 ) - 2 sin ( 2 )}{s ^{2} + 2 ^{2}}

= \frac{s cos ( 2 ) - 2 sin ( 2 )}{s ^{2} + 2 ^{2}}

= \frac{cos ( 2 ) s - 2 sin ( 2 )}{s ^{2} + 4}

\int \frac{x ^{2} - 16 x - 1}{( x - 1 ) ^{2} ( x ^{2} + 1 )} d x

\frac{\partial}{\partial z} (x y + z^{2})

\frac{\partial}{\partial x} (x^{y} ln (x))

\frac{\partial}{\partial L} (L^{\frac{1}{2}} K^{\frac{1}{2}})

\frac{\partial}{\partial y} (x + cos (x yz) - 1)

What is laplacetransform cos(2(t+1)) ?
The answer to laplacetransform cos(2(t+1)) is (cos(2)s-2sin(2))/(s^2+4)