What is (\partial)/(\partial z)(xy+z^2) ?

The answer to (\partial)/(\partial z)(xy+z^2) is 2z

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(\partial)/(\partial z)(xy+z^2)

\frac{\partial}{\partial z} (x y + z^{2})

2 z

Solution steps

\frac{\partial}{\partial z} (x y + z^{2})

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x y) + \frac{\partial}{\partial z} (z^{2})

\frac{\partial}{\partial z} (x y) = 0

\frac{\partial}{\partial z} (z^{2}) = 2 z

= 0 + 2 z

Simplify

= 2 z

\frac{\partial}{\partial x} (x^{y} ln (x))

\frac{\partial}{\partial L} (L^{\frac{1}{2}} K^{\frac{1}{2}})

\frac{\partial}{\partial y} (x + cos (x yz) - 1)

2 x, x^{2 - 3}

\frac{d}{d x} (sin (x) + \frac{2}{9} cot (x))

What is (\partial)/(\partial z)(xy+z^2) ?
The answer to (\partial)/(\partial z)(xy+z^2) is 2z