What is the integral from-2 to 2 of 3x^2 ?

The integral from-2 to 2 of 3x^2 is 16

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integral from-2 to 2 of 3x^2

\int_{- 2}^{2} 3 x^{2} d x

16

Solution steps

\int_{- 2}^{2} 3 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{- 2}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 2}^{2}

= 3 [\frac{x ^{3}}{3}]_{- 2}^{2}

Compute the boundaries:

\frac{16}{3}

= 3 \cdot \frac{16}{3}

Simplify

= 16

\frac{d}{d x} (\frac{cos ( 2 x )}{1 - sin ( 2 x )})

x \to 0 lim (\frac{x ^{5} + 7 x}{x})

\int \frac{x ^{2}}{81 + x ^{2}} d x

\int (\frac{x}{4}) d x

3 - 7 x

What is the integral from-2 to 2 of 3x^2 ?
The integral from-2 to 2 of 3x^2 is 16