What is the limit as x approaches 5+of ((x+1))/(x-5) ?

The limit as x approaches 5+of ((x+1))/(x-5) is infinity

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limit as x approaches 5+of ((x+1))/(x-5)

x \to 5 + lim (\frac{( x + 1 )}{x - 5})

\infty

Solution steps

x \to 5 + lim (\frac{x + 1}{x - 5})

\frac{x + 1}{x - 5} = (x + 1) \frac{1}{x - 5}

= x \to 5 + lim ((x + 1) \frac{1}{x - 5})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 5 + lim (x + 1) \cdot x \to 5 + lim (\frac{1}{x - 5})

x \to 5 + lim (x + 1) = 6

x \to 5 + lim (\frac{1}{x - 5}) = \infty

= 6 \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

3 x^{2} - 2 x

\int \frac{s}{s ^{2} + 3 s + 6} d s

x = - 2 y^{2} + 3 y - 5, x + 3 y = - 13

f (x) = 2 x + 1

f (x) = arcsin (\frac{1}{x})

What is the limit as x approaches 5+of ((x+1))/(x-5) ?
The limit as x approaches 5+of ((x+1))/(x-5) is infinity