What is the tangent of 3x^2-2x ?

The tangent of 3x^2-2x is y=(6a_{0}-2)x-3a_{0}^2

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tangent of 3x^2-2x

tangent of

3 x^{2} - 2 x

y = (6 a_{0} - 2) x - 3 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0}^{2} - 2 a_{0})

Find the slope of

y = 3 x^{2} - 2 x : \frac{d y}{d x} = 6 x - 2

Compute the slope of

y = 3 x^{2} - 2 x

x = a_{0} : m = 6 a_{0} - 2

Find the line with slope m=

6 a_{0} - 2

and passing through

(a_{0}, 3 a_{0}^{2} - 2 a_{0}) : y = (6 a_{0} - 2) x - 3 a_{0}^{2}

y = (6 a_{0} - 2) x - 3 a_{0}^{2}

\int \frac{s}{s ^{2} + 3 s + 6} d s

x = - 2 y^{2} + 3 y - 5, x + 3 y = - 13

f (x) = 2 x + 1

f (x) = arcsin (\frac{1}{x})

\int_{0}^{15} \frac{4}{5} x d x

What is the tangent of 3x^2-2x ?
The tangent of 3x^2-2x is y=(6a_{0}-2)x-3a_{0}^2