What is the integral from 0 to 15 of 4/5 x ?

The integral from 0 to 15 of 4/5 x is 90

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integral from 0 to 15 of 4/5 x

\int_{0}^{15} \frac{4}{5} x d x

90

Solution steps

\int_{0}^{15} \frac{4}{5} x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{4}{5} \cdot \int_{0}^{15} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{15}

= \frac{4}{5} [\frac{x ^{2}}{2}]_{0}^{15}

Compute the boundaries:

\frac{225}{2}

= \frac{4}{5} \cdot \frac{225}{2}

Simplify

= 90

y^{^{'}} + cot (x) y = csc (x)

\int e^{\frac{x}{2}} cos (x) d x

\frac{d}{d x} (8 e^{x} + x e^{x})

9 (t + 1) y^{^{'}} - 5 y = 20 t

\frac{\partial}{\partial s} (ln (r^{2} + s^{2} + 2))

What is the integral from 0 to 15 of 4/5 x ?
The integral from 0 to 15 of 4/5 x is 90