What is the solution for y^'+cot(x)y=csc(x) ?

The solution for y^'+cot(x)y=csc(x) is y= x/(sin(x))+(c_{1})/(sin(x))

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y^'+cot(x)y=csc(x)

y^{^{'}} + cot (x) y = csc (x)

y = \frac{x}{sin ( x )} + \frac{c _{1}}{sin ( x )}

Solution steps

y^{'} (x) + cot (x) y = csc (x)

Solve linear ODE:

y = \frac{x}{sin ( x )} + \frac{c _{1}}{sin ( x )}

y = \frac{x}{sin ( x )} + \frac{c _{1}}{sin ( x )}

\int e^{\frac{x}{2}} cos (x) d x

\frac{d}{d x} (8 e^{x} + x e^{x})

9 (t + 1) y^{^{'}} - 5 y = 20 t

\frac{\partial}{\partial s} (ln (r^{2} + s^{2} + 2))

\int e^{x} 25 - e^{2 x} d x

What is the solution for y^'+cot(x)y=csc(x) ?
The solution for y^'+cot(x)y=csc(x) is y= x/(sin(x))+(c_{1})/(sin(x))