What is (\partial)/(\partial x)(e^{9z}-xyz) ?

The answer to (\partial)/(\partial x)(e^{9z}-xyz) is -zy

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(\partial)/(\partial x)(e^{9z}-xyz)

\frac{\partial}{\partial x} (e^{9 z} - x yz)

- zy

Solution steps

\frac{\partial}{\partial x} (e^{9 z} - x yz)

Treat

z, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (e^{9 z}) - \frac{\partial}{\partial x} (x yz)

\frac{\partial}{\partial x} (e^{9 z}) = 0

\frac{\partial}{\partial x} (x yz) = zy

= 0 - zy

Simplify

= - zy

\int 3 x cot (x^{2}) d x

\frac{d}{d θ} (a sec^{2} (\frac{θ}{2}))

x \to - 1 lim (3 x^{2} - 7 x - 4)

\int (4 x^{3} - 2)^{2} d x

\frac{d}{d x} (\frac{e ^{x}}{x ^{4} + 1})

What is (\partial)/(\partial x)(e^{9z}-xyz) ?
The answer to (\partial)/(\partial x)(e^{9z}-xyz) is -zy