What is the integral of 20x^3-12x^2+6x ?

The integral of 20x^3-12x^2+6x is 5x^4-4x^3+3x^2+C

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integral of 20x^3-12x^2+6x

\int 20 x^{3} - 12 x^{2} + 6 x d x

5 x^{4} - 4 x^{3} + 3 x^{2} + C

Solution steps

\int 20 x^{3} - 12 x^{2} + 6 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 20 x^{3} d x - \int 12 x^{2} d x + \int 6 x d x

\int 20 x^{3} d x = 5 x^{4}

\int 12 x^{2} d x = 4 x^{3}

\int 6 x d x = 3 x^{2}

= 5 x^{4} - 4 x^{3} + 3 x^{2}

Add a constant to the solution

= 5 x^{4} - 4 x^{3} + 3 x^{2} + C

n = 1 \sum \infty \frac{7}{n ^{2} + 9}

x \to 0 + lim (\frac{e ^{x}}{e ^{x} - 1})

\frac{\partial}{\partial y} (e^{y^{2}} - e^{y})

f (r) = \frac{4}{3} π r^{3}

\int 3 y^{2} z + y e^{x} d x

What is the integral of 20x^3-12x^2+6x ?
The integral of 20x^3-12x^2+6x is 5x^4-4x^3+3x^2+C