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Popular >

4y^2ydx+xydy=0

Solution

4 y^{2} y d x + x y d y = 0

Solution

y = - \frac{1}{- 4 ln ( x ) + c _{1}}

Solution steps

4 y^{2} y d x + x y d y = 0

Solve separable ODE:

y = - \frac{1}{- 4 ln ( x ) + c _{1}}

y = - \frac{1}{- 4 ln ( x ) + c _{1}}

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Frequently Asked Questions (FAQ)

What is the solution for 4y^2ydx+xydy=0 ?
The solution for 4y^2ydx+xydy=0 is y=-1/(-4ln(x)+c_{1)}