What is (\partial)/(\partial x)(2*z*cos(x)) ?

The answer to (\partial)/(\partial x)(2*z*cos(x)) is -2zsin(x)

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(\partial)/(\partial x)(2zcos(x))

\frac{\partial}{\partial x} (2 \cdot z \cdot cos (x))

- 2 z sin (x)

Solution steps

\frac{\partial}{\partial x} (2 z cos (x))

Treat

z

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 z \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 2 z (- sin (x))

Simplify

= - 2 z sin (x)

x \to 0 lim (\frac{2 ln ( x + 1 )}{x})

3 e^{- x^{2}}

y = x^{3} sin^{2} (x)

f (x) = e^{x^{2} - x}

3 x + 1, at a = 8

What is (\partial)/(\partial x)(2*z*cos(x)) ?
The answer to (\partial)/(\partial x)(2*z*cos(x)) is -2zsin(x)