What is the derivative of y=x^3sin^2(x) ?

The derivative of y=x^3sin^2(x) is 3x^2sin^2(x)+sin(2x)x^3

What is the first derivative of y=x^3sin^2(x) ?

The first derivative of y=x^3sin^2(x) is 3x^2sin^2(x)+sin(2x)x^3

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derivative of

y = x^{3} sin^{2} (x)

3 x^{2} sin^{2} (x) + sin (2 x) x^{3}

Solution steps

\frac{d}{d x} (x^{3} sin^{2} (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{3}, g = sin^{2} (x)

= \frac{d}{d x} (x^{3}) sin^{2} (x) + \frac{d}{d x} (sin^{2} (x)) x^{3}

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (sin^{2} (x)) = sin (2 x)

= 3 x^{2} sin^{2} (x) + sin (2 x) x^{3}

f (x) = e^{x^{2} - x}

3 x + 1, at a = 8

\int sin (\frac{1 - x}{3}) d x

cos^{2} (ln (e^{2 x + 1} (- 2 x)))

\frac{3 e ^{- π s}}{s ^{2} + 9}

What is the derivative of y=x^3sin^2(x) ?
The derivative of y=x^3sin^2(x) is 3x^2sin^2(x)+sin(2x)x^3
What is the first derivative of y=x^3sin^2(x) ?
The first derivative of y=x^3sin^2(x) is 3x^2sin^2(x)+sin(2x)x^3