What is the derivative of 3x^2-2x+5 ?

The derivative of 3x^2-2x+5 is 6x-2

What is the first derivative of 3x^2-2x+5 ?

The first derivative of 3x^2-2x+5 is 6x-2

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\frac{d}{d x} (3 x^{2} - 2 x + 5)

6 x - 2

Solution steps

\frac{d}{d x} (3 x^{2} - 2 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (5) = 0

= 6 x - 2 + 0

Simplify

= 6 x - 2

\int (x y e^{x z}) d z

\int x I n x d x

\int - \frac{1}{( x - 1 ) ^{2}} d x

\frac{3 w ^{6} - w}{w}

(\frac{1}{( 4 - x ) ^{2}})^{^{'}}

What is the derivative of 3x^2-2x+5 ?
The derivative of 3x^2-2x+5 is 6x-2
What is the first derivative of 3x^2-2x+5 ?
The first derivative of 3x^2-2x+5 is 6x-2