What is the sum from n=0 to infinity of n/(n+2) ?

The sum from n=0 to infinity of n/(n+2) is diverges

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sum from n=0 to infinity of n/(n+2)

n = 0 \sum \infty \frac{n}{n + 2}

diverges

Solution steps

n = 0 \sum \infty \frac{n}{n + 2}

Apply Series Divergence Test:

diverges

= diverges

\frac{d}{d x} (\frac{x}{1 - 2 x})

\int x^{3} x^{2} + 15 d x

n = 1 \sum \infty \frac{1}{2 ^{n} ( n + 1 )}

x \to 9 lim (\frac{4 x}{x - 9})

y^{^{'}} \cdot (x - 1) + y \cdot (x - 2) = 0

What is the sum from n=0 to infinity of n/(n+2) ?
The sum from n=0 to infinity of n/(n+2) is diverges