What is the limit as x approaches 9 of (4x)/(x-9) ?

The limit as x approaches 9 of (4x)/(x-9) is diverges

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limit as x approaches 9 of (4x)/(x-9)

x \to 9 lim (\frac{4 x}{x - 9})

diverges

Solution steps

x \to 9 lim (\frac{4 x}{x - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 9 + lim (\frac{4 x}{x - 9}) = \infty

x \to 9 - lim (\frac{4 x}{x - 9}) = - \infty

= diverges

y^{^{'}} \cdot (x - 1) + y \cdot (x - 2) = 0

\frac{1}{( s + 2 ) ( s + 3 )}

\frac{d}{d x} (e^{4 x + 1})

\int_{- 1}^{0} 1.5 x^{2} d x

y - x y^{^{'}} = 1 x^{2} y^{^{'}}

What is the limit as x approaches 9 of (4x)/(x-9) ?
The limit as x approaches 9 of (4x)/(x-9) is diverges