What is the integral from-1 to 0 of 1.5x^2 ?

The integral from-1 to 0 of 1.5x^2 is 0.5

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integral from-1 to 0 of 1.5x^2

\int_{- 1}^{0} 1.5 x^{2} d x

0.5

Solution steps

\int_{- 1}^{0} 1.5 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 1.5 \cdot \int_{- 1}^{0} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{0}

= 1.5 [\frac{x ^{3}}{3}]_{- 1}^{0}

Simplify

= 1.5 [0.33333 \dots x^{3}]_{- 1}^{0}

Compute the boundaries:

0.33333 \dots

= 1.5 \cdot 0.33333 \dots

Simplify

= 0.5

y - x y^{^{'}} = 1 x^{2} y^{^{'}}

\frac{\partial}{\partial y} (2 (y + 4)^{3} (x - 5))

x \to - 1 lim (7 x - 2 x^{2})

y = 1 + 2 x

y^{^{''}} + 12 y^{^{'}} + 117 y = 0

What is the integral from-1 to 0 of 1.5x^2 ?
The integral from-1 to 0 of 1.5x^2 is 0.5