What is the derivative of y=sqrt(1+2x) ?

The derivative of y=sqrt(1+2x) is 1/(sqrt(1+2x))

What is the first derivative of y=sqrt(1+2x) ?

The first derivative of y=sqrt(1+2x) is 1/(sqrt(1+2x))

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derivative of

y = 1 + 2 x

\frac{1}{1 + 2 x}

Solution steps

\frac{d}{d x} (1 + 2 x)

Apply the chain rule:

\frac{1}{2 1 + 2 x} \frac{d}{d x} (1 + 2 x)

= \frac{1}{2 1 + 2 x} \frac{d}{d x} (1 + 2 x)

\frac{d}{d x} (1 + 2 x) = 2

= \frac{1}{2 1 + 2 x} \cdot 2

Simplify

\frac{1}{2 1 + 2 x} \cdot 2 : \frac{1}{1 + 2 x}

= \frac{1}{1 + 2 x}

y^{^{''}} + 12 y^{^{'}} + 117 y = 0

\frac{d}{d x} (\frac{x}{7 x + 8})

\frac{\partial}{\partial x} (2 x - \frac{3}{x ^{2}} + y)

y = 2 - x

y^{^{''}} - y^{^{'}} + 5 y = 3

What is the derivative of y=sqrt(1+2x) ?
The derivative of y=sqrt(1+2x) is 1/(sqrt(1+2x))
What is the first derivative of y=sqrt(1+2x) ?
The first derivative of y=sqrt(1+2x) is 1/(sqrt(1+2x))