What is (\partial)/(\partial x)(2x-3/(x^2)+y) ?

The answer to (\partial)/(\partial x)(2x-3/(x^2)+y) is 6/(x^3)+2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(2x-3/(x^2)+y)

\frac{\partial}{\partial x} (2 x - \frac{3}{x ^{2}} + y)

\frac{6}{x ^{3}} + 2

Solution steps

\frac{\partial}{\partial x} (2 x - \frac{3}{x ^{2}} + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) - \frac{\partial}{\partial x} (\frac{3}{x ^{2}}) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (\frac{3}{x ^{2}}) = - \frac{6}{x ^{3}}

\frac{\partial}{\partial x} (y) = 0

= 2 - (- \frac{6}{x ^{3}}) + 0

Simplify

= \frac{6}{x ^{3}} + 2

y = 2 - x

y^{^{''}} - y^{^{'}} + 5 y = 3

\frac{d}{d x} (2 (1 - x))

y^{^{''}} + 4 y = x^{2} + 3 e^{x}

\frac{\partial}{\partial x} (cos (k x))

What is (\partial)/(\partial x)(2x-3/(x^2)+y) ?
The answer to (\partial)/(\partial x)(2x-3/(x^2)+y) is 6/(x^3)+2